Suppose that the antenna lengths of woodlice are approximate

Suppose that the antenna lengths of woodlice are approximately normally distributed with a mean of 0.23 inches? Round your answer to at least four decimal places. 0.05 inches. What proportion of woodlice have antenna lengths that are at most inches and a standard deviation of

Solution

P(X<=0.23) = P((X-mean)/s <(0.23-0.25)/0.05)

=P(Z<-0.4) =0.3446 (from standard normal table)

i.e. 34.46%