Homework Sourse14 A card is drawn from a standard deck of 52 cards a Find t
Solution
14)
a)
Total number of red card in a deck = 13 hearts + 13 diamonds = 26
probability that a card is red = 26/52 = 0.5
b)
total number of aces in a deck = 4
probability that a card is ace = 4/52 = 1/13 or 0.0769
c)
probability that the card is two of diamonds = 1/52 or 0.0192
15)
a)
let
H = head and T = tail
sample space = {HHH,HHT,HTH,THH,HTT,THT,TTH,TTT}
total number of possibilities of exactly one head = 3
required probability = 3/8 or 0.375
b)
pobability of all heads = 1/8 = 0.125
16)
total ways of picking 5 cards = 52C5
total ways of picking 5 diamonds = 13C5
required probability = 13C5/52C5
= 1287/2598960
= 33/66640 or 0.000495
17)
a)
total ways of choosing 8 workers = 41C8
total ways of choosing all first shift workers = 24C8
required probability = 24C8/41C8= 0.007697
b)
total ways of choosing all second shift workers = 17C8
required probability = 17C8/41C8= 0.0002544
c)
total ways of choosing 6 first shift workers = 24C6
remaining 2 workers can be choosen as = 17C2
required probability = 24C6 * 17C2/41C8= 0.1916
d)
total ways of choosing four second shift workers = 17C4
remaining 4 workers are choosen as = 24C4
required probability = 24C4 * 17C4/41C8= 0.2647
