p atm 0 V cm3 0 1000 2000 3000 SolutionNumber of moles n 9

p (atm) . 0 V (cm3) 0 1000 2000 3000

Solution

Number of moles n = 9.22 mol

Temparture of the gas at point 1 is T = PV /nR

Where P = Pressure at point 1 = 3 atm = 3 x1.01 x10 ⁵ Pa

           V = Volume at point 1 = 1000 cm 3 = 1000 x10 ^-6 m ³

           R = Gas cosnstant = 8.314 J / mol K

Substitute values you get , T = ( 3x1.01 x10 ⁵)(10 ^-3 ) /(9.22 x8.314 )

                                          = 3.952 K

Volume at point 2 is V \' = 3000 cm ³

Pressure at point 2 is P \' = 1 atm

Temprature at point 2 is T \' = T = 3.952 K

Pressure at final point P \" = P = 3 atm

Temprature at final point T \" = ?

At constant volume , T \" / T \' = P \" / P \'

    T \" = T \' ( P \" / P \')

         = 3.952 ( 3 atm / 1 atm )

        = 3.952 ( 3)

        = 11.85 K

Relation between kelvin scale (K) and Fahrenheit scale (F ) is

(K-273)/(373-272) = (F-32) /(212-32)

(K-273) /100 = (F-32) /180

            F-32 = (180/100) (K-273)

                   = (9/5)(11.85 -273 )      reading in kelvin scale K = 11.85 K

                   =(9/5)(-261.15)

                   = -470

                F = 32 -470

                   = -438 ^o F