A mixture of methanol and propyl acetate contains 350 wt met

A mixture of methanol and propyl acetate contains 35.0 wt% methanol.

Using a single dimensional equation, I determined the g-moles of methanol in 380.0 kg of the mixture to be 4151.06 g-moles methanol. So, the flow rate of propyl acetate in the mixutre is to be 220.0 lb-mole/h. What must the mixture flow rate be in lb_mh?

Solution

METHANOL:

Formula: CH₃OH

Boiling point: 64.7 °C

Density: 792 kg/m³

Molar mass: 32.04 g/mol

propyl acetate:

Boiling point: 102 °C

Formula: C₅H₁₀O₂

Molar mass: 102.131 g/mol

Density: 888 kg/m³

200x10³g(0.15) = 30,000 g CH4

mole: n = m/M = 0.85(200x10³g)/74.08 g/mol) = 2294.8 mol

Propylene glycol

Formula: C₃H₈O₂

100lb-mol/h/2294.8 mol = 0.04357 lbm/h

The mixture flow rate is 0.04357 lbm/h.