Calculate the stopping power in aluminum for a 6 MeV alpha p

Calculate the stopping power in aluminum for a 6 MeV alpha particle.

Solution

The maximum energy loss Emax of the particle in each particle collision

Emax = E/459 Aion (MeV)

given E = 6 MeV

and for alpha particle Aion = 4

so Emax = 6 / (459 * 4)

                 = 0.003 Mev

stopping power = 6 - 0.003

                      = 5.997 MeV