find the area between z248 and z83SolutionNormal Distributio

find the area between z=-2.48 and z=-.83

Normal Distribution
Mean ( u ) =0
Standard Deviation ( sd )=1
Normal Distribution = Z= X- u / sd ~ N(0,1)
To find P(a < = Z < = b) = F(b) - F(a)
P(X < -2.48) = (-2.48-0)/1
= -2.48/1 = -2.48
= P ( Z <-2.48) From Standard Normal Table
= 0.00657
P(X < -0.83) = (-0.83-0)/1
= -0.83/1 = -0.83
= P ( Z <-0.83) From Standard Normal Table
= 0.20327
P(-2.48 < X < -0.83) = 0.20327-0.00657 = 0.1967