please solve and explain 360 such that sin 50cos eioose2 7 F

please solve and explain

360° such that sin 50\'-cos ei-oose2 7. Find two angles 0 s 0 ,22 ?

Solution

sin 50 can be written as

sin (90 - 40 )

applying sin ( 90 - theta ) formula

sin (90- theta ) = cos theta

hence , sin 50 = cos 40

so, theta 1 = 40 degrees

Now cos is +ve in IVrth qudrant.

sin50 = cos40 = cos( 360 -40) = cos320

theta 2 = 320 degrees