According to data from the Environmental Protection Agency t
According to data from the Environmental Protection Agency, the average daily water consumption for a household of four people in the United States is approximately at least 243 gallons. (Source: http://www.catskillcenter.org/programs/csp/H20/Lesson3/house3.htm) Suppose a state agency plans to test this claim using an alpha level equal to 0.05 and a random sample of 100 households with four people.
 
 Calculate the probability of committing a Type II error if the true population mean is 230 gallons. Assume that the population standard deviation is known to be 40 gallons.
| 0.1412 | 
Solution
Test Used: Z-Test For Single Mean
 Set Up Hypothesis
 Null, H0: U>=243
 Alternate, H1: U<243 ( left tailed - test)
 Test Statistic
 Population Mean(U)=243
 Standard Deviation(S.D)=40
 Number (n)=100
 we use Test Statistic (Z) = x-U/(s.d/Sqrt(n))
 Zo=x-243/(40/Sqrt(100)
 Zo =x-243/(40/10)
 Zo =x-243/4
 Critical Value
 The Value of Z  at LOS 0.05% is -1.645
=> x-243/4 = -1.645
 => x = 236.42
The true population is given as 230
 P( Z <=x-U/(s.d/Sqrt(n)) = P( Z <= 236.42-230/(40/Sqrt(100)
                        = P( Z <= 1.605)
                        = 0.9458  
                      
 The Probability of Type II Error (Beta) = 1 - 0.9458 = 0.0542 ~ Near by Value 0.0537 [ANSWER]

