45 50 62 48 66 59 Find the standard deviation of this sample
45, 50, 62, 48, 66, 59
Find the standard deviation of this sample of numbers. Round your answer to at least two decimal places
.
Solution
Getting the mean, X,
X = Sum(x) / n
Sum(x) = 330
Thus,
X = 55
Setting up tables,
x x - X (x - X)^2
45 -10 100
50 -5 25
62 7 49
48 -7 49
66 11 121
59 4 16
Thus, Sum(x - X)^2 = 360
Thus, as
s^2 = Sum(x - X)^2 / (n - 1)
As n = 6
s^2 = 72
Thus,
s = 8.485281374 [answer]
