Can someone help me figure out either 9 or 10 My instructor
Can someone help me figure out either 9 or 10. My instructor is avoiding helping us.
Solution
9.a (fog)(1)= f(g(1))
And from table g(1)=0
substituting g(1)=0 in f(g(1))=f(0)
And from table f(0)=-1
b. (fog)(-1)= f(g(-1))
And from table g(-1)=0
Therefore f(g(-1))=f(0)
And f(0)=-1
(fog)(-1)=-1
c. (gof)(-1)=g(f(-1))
And f(-1)=-3
Therefore g(f(-1))=g(-3)
And from table g(-3)=8
Therefore (gof)(-1)= 8
d. (gof)(0)= g(f(0))
And from table f(0)=-1
Therefore g(f(0))= g(-1)
And from table g(-1)= 0
THerefore (gof)(0)=-1
e. (gog)(-2)= g(g(-2))
And from table g(-2)=3
therefore g(g(-2))=g(3)
And from table g(3)=8
Therefore (gog)(-2)=8
f.(fof)(-1)=f(f(-1))
And from table f(-1)=-3
Therefore f(f(-1))=f(-3)
And from table f(-3)=-7
Therefore (fof)(-1)=-7
Therefore (fog)(1)=0

