A beltdriven generator supplies 875 kW at 95 percent efficie
A belt-driven generator supplies 875 kW at 95 percent efficiency. If the loss in the drive belt is 2.5 percent, calculate the horsepower of the engine needed to drive the generator.
Solution
GIVEN OUT PUT OF GENERATOR 875 KW
INPUT OF GENERATOR IS 875/(0.95)
=921.052KW
2.5 PERCNTAGE ARE LOSS MEANS 97.5 PERCENTAG ARE USED
ENGINE POWER=(921.052/0.975)
944.669KW
745W=1 HP
944.669/0.745
=1267hp
