Can someone help me with this question by fully breaking it

Can someone help me with this question by fully breaking it down for me?

A curve is given parametrically by the equations x = sin(4t);y = cos(4t);z = 2t 3/2. Compute the parametric equations of the tangent line at the point when t = 1.

Solution

x\' = 4cos4t
y\' = -4sin4t
z\' = 3t^1/2
When t= 1,
x\' = 4cos4
y\' = -4sin4
z\' = 3
So x\'^2 + y\'^2 = 16z\'/3