in a batch machine operation steup time is 15 hr and batch s

in a batch machine operation, steup time is 1.5 hr and batch size is 80 units. the cycle time consists of handling time of 30 sec and processing time of 1.37 min. one part is produced each cycle. tool changes must be performed every 10 parts and this takes 2 min. determine a) average cycle time b) time to complete the batch and c) average productioin rate.

Solution

Solution :

a) Average cycle time = handling time + processing time + tool change time / 10

Average cycle time = 30 secs + 97 secs + 120 secs / 10

Average cycle time = 24.7 seconds

b) time to complete the batch = n (setup time + Q OC_t + Non operation time includes handling & tool changes)

time to complete the batch = 1 ( 1.5 hr + 80 X 0.00686 hr + 0.00833 hr + 0.033hr)

time to complete the batch = 2.09 hr

c) average productioin rate = no of parts produced per batch / average cycle time

average productioin rate =60 / (B_t / Q)

average productioin rate =60 / ( 2.09 / 80)

average productioin rate = 2,297 units