you and your brother started biking at noon from places that

you and your brother started biking at noon from places that are 52 miles apart. You rode toward eachother and met at 2:00 p.m. Your brother\'s average speed was 4 mi/h faster than your average speed. Find both speeds. So how do i begin this problem, i dont know what to do.

Solution

D=RT
lET X & (X=4) BE THE 2 SPEEDS.
52=(X+X+4)*2
52=(2X+4)*2
52=4X+8
4X=52-8
4X=44
X=44/4
X=11 MPH FOR THE SLOWER RIDER.
11+4=15 MPH FOR THE FASTER RIDER.
PROOF:
52=(11+15)*2
52=26*2
52=52