A researcher wishes to estimatethe proportion of adults who
A researcher wishes to estimatethe proportion of adults who have high speed internet acess. What sample size should be obtained if she wishes the estimate to be within 0.03 with 90% confidence if (a) she uses a prvious estimate of 0.58? (b) she does not use any prior estimates.
Solution
a)
 Compute Sample Size ( n ) = n=(Z/E)^2*p*(1-p)
 Z a/2 at 0.1 is = 1.64
 Samle Proportion = 0.58
 ME = 0.03
 n = ( 1.64 / 0.03 )^2 * 0.58*0.42
 = 727.985 ~ 728
b)
 Compute Sample Size ( n ) = n=(Z/E)^2*p*(1-p)
 Z a/2 at 0.1 is = 1.64
 Samle Proportion = 0.5
 ME = 0.03
 n = ( 1.64 / 0.03 )^2 * 0.5*0.5
 = 747.111 ~ 748

