A freequency distribution is shown below Complete parts a th

A freequency distribution is shown below. Complete parts (a) through (e).

The number of overtime hourss worked in one week per employee

overtime hours 0 1 2 3 4 5 6

Employees 7 18 27 57 44 33 15

a) Use the frequency distribution to construct a probablity distribution.

x P(x)

0 ?

1 ?

2 ?

3 ?

4 ?

5 ?

6 ?

(Round to the nearest thousandth as needed)

B) Find the mean of the probability distribution.

u= ? ( Round to the nearest tenth as needed.)

C) Find the variance of the probability distribution.

o^2=? (round to the nearest tenth as needed.)

d) Find the standard deviation of the probabiliity distribution.

0= ? ( Round to the nearest tenth a neeeded.)

e) Interpret the results in the context of the real-life situation.

a) An employee workks an average of 1.5 overtime hours per week with a standard diviation of approximately 3.4 hours.

b) Ann employeee works an average 3.4 of overtime hours per week with a standard deviation of approximately 7 hours.

c) An employee works an average of 3.4 overtime hours per week with a standard deviation of approximately 1.5 hours.

d) An employee works an average of 2.2 overtime hours per week with a standard deviation of approximately 1.5 hours.

Solution

Mean is 3.4 mostly in the middle of the x value. Hence not skewed much.

But not fully symmetrical.

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a) c) An employee works an average of 3.4 overtime hours per week with a standard deviation of approximately 1.5 hours.

is the answer