Another hospital that looks exactly the same is located in M

Another hospital that looks exactly the same is located in Miami, F loridaThe terrain is open. The ing is enclosed. The overall height of the hospital is 45 ft and you may assume that the windward pressure is constant (does not vary along the height). Use G-0.85, and Ka-1.0. Exposure Determine the pressures on the four sides of the building assuming that it is experiencing C suction or intermal expansion. Use the diagrams that represent plan views below to display your answers provide calculations on attached documents. With respect to the windward side, the building has a width of 30 ft and a length of 60 ft. Prob. 1-22 Internal Suction: Internal Expansion p= Wind Wind

Solution

Given: Building is enclosed having Overall height = 45ft

length = 60ft ( Windward side )

width = 30ft   ( Windward side )

and G = 0.85, K_zt = 1, Exposure = C and Windward Pressure is constant

Findout: Pressure on 4sides of the building assuming that is experencing internal suction.

Answer: We know that, By using Generic Formula

Wind load F = A * P * Cd * Kz * G ................1

where, A = Area = length * width = 60*30 =1800ft²

P = Wind Pressure = constant =1

Cd = Drag coefficient = 2 ( For buildings Long flat plate = 2

Kz = Exposure coefficient = 1 Shot flat plate = 1.4 )

G = Gust response factor = 0.85

Substituting all values in equation(1) we get,

F = 1800*1*2*1*0.85

= 3060lbs.

Wind Pressure P = 0.00256 * V² V = Wind Speed

This formula is based on the American Society of Civil Engineering Codes and 0.00256 is coefficient is result of a calculation for air density and gravitational acceleration.

By given in Question it is mentioned that Windward Pressure is constant ,hence Pressure on 4sides of the building is also constant and it is varies by Windspeed respectively.