g S ag circles t t l 6 4b 4x2 4y2 36y 5 0 Center Radius t 36

g S ag circles t t l 6 4b) 4x2 4y2 36y 5 0 Center: Radius: t 36 y

The general form of the circle is x² + y² + 2gx + 2fy + c = 0 where g = -h and f = -k and (h,k) is the center

and c = h² + k² - r²

Lets divide the given equation by 4, which gives us x² + y² + 9y + 5/4 = 0.

Since there is no coefficient of x, it means h = 0

from coefficient of y, 9 = 2f. Therefore f =9/2 = -k or k = -9/2

Therefore the center of the circle = (0,-9/2) or (0,-4.5)

c = 5/4 = h² + k² - r² where h = 0 and k = -9/2

Therefore 5/4 = 0 + (-9/2)² - r²

r² = 81/4-5/4 = 76/4 = 19

r = Sqrt(19) = 4.36