Find the eccentricity of the hyperbola 15y2 522 15 What is

Find the eccentricity of the hyperbola. 15y^2 - 52^2 = 15 What is the eccentricity? (Type an integer or decimal rounded to the nearest tenth as needed.)

Solution

15y^2 - 5x^2 =15

15y^2 /15 -5x^2 = 15/15

y^2 -(x^2)/3 =1

comparing it a = 1 b = sqrt(3)

e = sqrt [ (a^2+b^2) /a)

e = sqrt [(1+3)/1)

e = sqrt(4)

e=2