Unpolarized light with intensity I0 is incident on an ideal

Unpolarized light with intensity I_0 is incident on an ideal polarizing filter. The emerging light strikes a second ideal polarizing filter whose axis is at 45.0degree to that of the first. Determine the intensity of the beam after it has passed through the second polarizer. Enter the factor only. For example, enter 0.250, that means your answer is I = 0.250 I_0 Determine its state of polarization. The light is linearly polarized along the axis of the first filter. The light is linearly polarized along the axis of the second filter. The light is linearly polarized perpendicular to the axis of the second filter. The light is linearly polarized perpendicular to the axis of the first filter.

Solution

Intensity of unpolarized light = Io

Intensity of the polarized light after passed through first polarizer I = Io/2

Intensity of the polarized light after passed through second polarizer I \' = I cos ² 45

              I \' = I(0.5)

                 =(Io/2)(0.5)

                = 0.25 Io

(b). The light is linearly polarized along the axis of the second filter