A beam of unpolarized light of intensity I0 passes through a

A beam of unpolarized light of intensity I0 passes through a series of ideal polarizing filters with their polarizing directions turned to various angles as shown in (Figure 1)

Part A

What is the light intensity (in terms of I0) at point A?

Part B

What is the light intensity (in terms of I0) at point B?

Part C

What is the light intensity (in terms of I0) at point C?

Part D

If we remove the middle filter, what will be the light intensity at point C?

Solution

a) IA= I0 / 2

b) IB = I0 / 2 * cos 60 * cos 60

= 0.125 I0

c) IC = I0 / 2 * cos 60 * cos 60 * cos (90 - 60)

= 0.0937 I0

d) IC = I0 / cos2 90

= 0

A beam of unpolarized light of intensity I0 passes through a series of ideal polarizing filters with their polarizing directions turned to various angles as sho

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