A beam of unpolarized light of intensity I0 passes through a
A beam of unpolarized light of intensity I0 passes through a series of ideal polarizing filters with their polarizing directions turned to various angles as shown in (Figure 1)
Part A
What is the light intensity (in terms of I0) at point A?
Part B
What is the light intensity (in terms of I0) at point B?
Part C
What is the light intensity (in terms of I0) at point C?
Part D
If we remove the middle filter, what will be the light intensity at point C?
Solution
a) IA= I0 / 2
b) IB = I0 / 2 * cos 60 * cos 60
= 0.125 I0
c) IC = I0 / 2 * cos 60 * cos 60 * cos (90 - 60)
= 0.0937 I0
d) IC = I0 / cos2 90
= 0

