Chapter 4 Second Law of Ther modynamics 1 A Carnot engine o
     Chapter 4 - Second Law of Ther modynamics 1.) A Carnot engine operates between 500 K and 300 K. The engine contains 100 moles of ideal gas as the working material. The initial volume of the gas before expansion of stroke 1 is 410.3L After the first expansion stroke, the volume is 1641.2 L a.) How much work is done per cycle for this engine? b.) If the gas is monatomic, what is the volume of the gas after the adiabatic stroke 2 is completed? c.) What is the volume of the gas after the completion of stroke 3?  
  
  Solution
a)
Wtot= -nRT1ln(V2/V1) -nRT2ln(V1/V2)
=-nR ln(V2/V1)(T1-T2)
Substitute the values.
Wtot=-(100moles)(8.314 J mol-1 K-1)ln(1641.3L / 410.3L) (500K - 300K)
=230523.15 J
=2.30X105J
b)
For monatomic gas, the molar heat capacity at constant volume is Cv=1.5R
The ratios of V2,V3and T2,T1are related as,
V2/V3=(T2/T1)Cv/R
V3=V2(T1/T2)Cv/R
=1641.2L (500K/300K) 1.5
=3531.3L
C)
The ratios of volume can be written as,
V2/V3=V1/V4
V4=(V1V3)/V2
=(410.3L * 3531.3L)/ 1641.2L
=882.8L

