In a recently conducted animal research regarding swine surv

In a recently conducted animal research regarding swine survival the following data was collected.

a) Let A represent the drug provided (A₁=drug 1, A₂= drug2). Let B represent the pig\'s survival. (B₁=survived, B₂= died). For each cell, calculate the joint probability. Meaning calculate P(A_1,B₁), P(A₁B_2), P(A₂B₁), P(A₂B₂). Place these probabilities in the following table.

b) For each row and column, calculate the arginal probability. In other words, calculate teh four marginal probabilities, P(A₁), P(A₂), P(B₁), P(B₂). Place in the following table with results from a. (recall marginal probability).

Independence of events means that P(A_IB_j)= P(A_I) x P(B_j) for all values of i and j. For true independence of events, the joint (cell) probabilities should equal the appropriate marginal probabilities multiplied by each other. In other words, you should be able to multiply the row and column marginal probabilites to obtain the cell probability. if this is not the case, then the events are not truly independent from a noninferential point of view. demonstrate that survival and drug choice are not independent solely based on the definition of independentce. In other words, investicate if P(A_iB_j)= P(A_I) x P(B_J) for all values of i and j.

d. Assume that there are 2 deths and 12 survivors in the given population. what is the probability that durg 1 would result in 0 deaths if the results of the study were truly random? model as a hypergeometric ( oftne called fishers exact test,) do you think there is sufficient evidnece to suggest different outcomes based on drug selection?

Solution

a)

b)

for finding the probability you just need to divide the number of for example drug 1 with survived is 7

divided by total

I can gladly help you with all your question. But you should post it in a new question.