Show that in a right triangle the inradius circumradius and
Show that in a right triangle, the inradius, circumradius, and semiperimeter are related by the formula s = r + 2R.
Solution
Show that in a right triangle, the inradius, circumradius, and semiperimeter are related by the formula s = r + 2R
. Solution
Let c by the length of the hypotenuse, and a and b the lengths of the sides.
Then R = c/2,
s = (a + b + c)/2, and r = ab/(a + b + c)
Since c = a 2 + b 2, we get
r = ab (a + b + c) = ab(a + b c) (a + b) 2 c 2 = a + b c 2 = s c = s 2R.
