Consider the position vs time graph for a moving car below D
Solution
1 ) car average speed = total distance tranvelled / total time = 30m / 6 sec = 5 m/sec
2 ) average velocity = total displacement / time = 0 , since he came back to the starting point , he cover to displacement
3) Object 2 finishes a head of Object 1
4)velocity V = distance / time = 15/ 6 = 2.5 m/sec , position after 10 sec = V * time = 2.5 * 10 = 25 m
5) distance = displacement ; when we move in a straight line ; i,e you walk 20 feet from teacher desk and sit
6)acceleration = change in velocity / time = 40 - 30 / 1sec or 45-40 /1sec = 5 km/h/s
7) A greater distance than the second before ; since acclerating bodys cover more distance with every sec time.
