An information technology company produces 48 of its compute

An information technology company produces 48% of its computer chips at a plant in St. Louis and the remainder of its chips at a plant in Chicago. It is known that 0.6% of the chips produced in St. Louis are defective, while 0.8% of the chips produced at the plan in Chicago are defective. What is the probability that a randomly chosen computer chip produced by this company is defective and was produced in St. Louis?

Solution

P(def and St. Louis) = P(St. Louis) P(def|St. Louis) = 0.48*0.006

= 0.00288 [ANSWER]