For the tank shown in Fig 322 determine the reading of the b

For the tank shown in Fig. 3.22, determine the reading of the bottom pressure gage in kPa (gage) if the top of the tank is vented to the atmosphere and the depth of the oil h

Solution

Given

specific gravity of oil, sg = 0.95

Hence, density of oil

rho = sg X density of water

= 0.95 X 1000 = 950 kg/m³

Since the oil is at rest, and the top of the tank is vented to the atmosphere,

Hence from hydrostatic law, bottom gauge pressure reading

P_g = rho X g X h

where g is the gravitational acceleration

P_g = 950 X 9.81h

P_g = 9319.5h Pa

= 9319.5h / 1000

P_g = 9.319h kPa (where h is in metres)........................................(Answer)