Suppose that x is normally distributed with a mean of 10 and

Suppose that x is normally distributed with a mean of 10 and a standard deviation of 3. Find P(x 6). Note: Round your answer, if necessary, to two places after the decimal. Please express your answer with two places after the decimal.

Solution

For x=6

z=(x-mu)/sigma

=(6-10)/3

=2.67

Thus P(X<6)

=P(z<2.67)

=0.9962