Homework SourseA simple random sample of 37 observations is derived from a
A simple random sample of 37 observations is derived from a normally distributed population with a known standard deviation of 6.4. Use Table 1.
Compute the margin of error with 99% confidence. (Round intermediate calculations to 4 decimal places, \"z\" value and final answer to 2 decimal places.)
| A simple random sample of 37 observations is derived from a normally distributed population with a known standard deviation of 6.4. Use Table 1. |
Solution
b)
Margin of Error = Z a/2 * (sd/ Sqrt(n))
Where,
x = Mean
sd = Standard Deviation
a = 1 - (Confidence Level/100)
Za/2 = Z-table value
Mean(x)=173.767
Standard deviation( sd )=6.4
Sample Size(n)=37
Margin of Error = Z a/2 * 6.4/ Sqrt ( 37)
= 2.58 * (1.0522)
= 2.7146
c)
WITH 95% C.I
Margin of Error = Z a/2 * 6.4/ Sqrt ( 37)
= 1.96 * (1.0522)
= 2.0622
