create a program using sequential search in c or java that f

create a program using sequential search in c++ or java that finds the key and index of the array where the key was found. If key not found output it not in the array. The range of numbers is 1-100

Solution

public class HelloSequential{

public static int sequentialSearch(int[] arr, int key){ //method for the operation sequential search,passing two parameters array and key

int size = arr.length;   
int i=0;
while(i<size){
if(arr[i] == key){
System.out.println(\"Key \"+key+\" found at index: \"+i); //if key is found here printing the index of the found key
break;}
else
i++;
  
}
if(i==size) //handling the case when key is not found
System.out.println(\"Key is not in the array\");

return 0;
}
  

public static void main(String[]args){
  
           Scanner sc=new Scanner(System.in);
           System.out.println(\"enter the size of the array\"); //asking for the size of input array from the user
           int n=sc.nextInt();
int arr[]=new int[n]; //declaring input array
       System.out.println(\"enter the values of the array,please enter the values within the range of 1 to 100 \ \"); //asking the input values from the user
       for(int i=0;i<n;i++)
       arr[i]=sc.nextInt();
System.out.println(\"enter the search key\"); //asking the key to be searched from the user
int searchKey = sc.nextInt();
sequentialSearch(arr, searchKey); //calling the function
  
}
} //end of the code

***********Output************
enter the size of the array
5   
enter the values of the array,please enter the values within the range of 1 to 100   
  
1   
5   
7   
4   
12
enter the search key
8   
Key is not in the array   
*************Output************
Please let me know in case of any doubt.