In the problem t is a real number and P x y is the point on

In the problem, t is a real number and P = (x, y) is the point on the unit circle that corresponds to t. Find the exact value of the indicated trigonometric function of t. (Squareroot 21/5, 2/5) Find sec t. 5 Squareroot 21/21 Squareroot 21/2 5/2 2 Squareroot 21/21

Solution

P = (x, y) = ( sqrt21/5 , 2/5)

Now right anglled triangke formed with base and height of x and y units

So, hypotenuse = sqrt(x^2 +y^2) = sqrt((sqrt(21)/5)^2 + (2/5)^2 )

= sqrt((21+4)/25)

= 1

Son cost = sqrt21/5/1 = sqrt(21)/5

sect = 5/sqrt21 = 5sqrt21/21

Option A