Given the right triangles MLK and PLN below PL 12 KN 2 and
     Given the right triangles MLK and PLN below; PL = 12, KN =2 and cos(L) = 2/3.  Find the length of KM.   
  
  Solution
Soution:
Given that
In above figure
 In triangle LNP ( N is a right angle )
therefore
Cos(L) = LN/ PL
LN/12 = 2/3 ( Given in question Cos(L) =2/3 and PL = 12
LN = 12 * (2/3) = 8
LN = 8
Now again in triangle LKM which right angled at K
LK = LN +NK
LK = LN + NK = 8 +2 = 10 ( Given NK = 2 and LN = 8 as per our last calculation)
LK = 10
Again in triangle LKM
Sin (L) = ( 1– Cos²(L) = (1-(2/3)²) = (5/9) = 5/3
and tan (L) = sin (L) /Cos(L) =KM/LK = (5/3)/(2/3)
KM / 10 = 5/2
KM = 55
Answer

