1 find the indefinite integral u2 U32 du 2 find the indefini

Solution

a) Let \\(u^3 + 2 = t; u^2 du = dt/3\\) = \\(2\\sqrt{(u^3 + 2)^3}/9 + c\\) b) Put 6x = t, dt/6 = dx \\(- \\sin (6x)/6 + c;\\) c) Put cos x = t, -sin x dx = dt \\((1/3)(\\cos x)^{-2}\\)