Find the standard form of the equation of a quadratic functi

Find the standard form of the equation of a quadratic function that has a vertex at (-3, 4) and passes through the point (0, 22)

vertex = (-3,4)

passes through (0,22)

standard quadratic equation is y = a(x-h)^2 + k

where h,k is the vertex

plugging the values we get

22 = a(0-(-3)) + 4

22 = 3a + 4

subtracting 4 from both sides

22-4 = 3a

18 = 3a

a = 6

therefore equation is

y = 6 ( x+3)^2 + 4

y = 6(x^2+6x+9) + 4 = 6x^2 +36x + 63