The perimeter of a rectangle is 36 inches the length exceeds

The perimeter of a rectangle is 36 inches. the length exceeds the width by 4 inches. what is the length and width
length =
width =

perimeter of a rectangle with length l and width w is given by 2(l+w)
now given 2(l+w)=36 -------------- 1
and l=w+4 ------------------ 2
so from eq.1 l+w=18
and substituting the value of l from eq.2

we get w+4+w=18
=> 2w+4=18
=> 2w=14
=> w=7
so length=11

width=7