Determine the nature of the solutions of the equation 4x2 1

Determine the nature of the solutions of the equation. 4x^2 - 16x + 16 = 0 The equation has A. two real solutions. B. one real solution. C. two non-real solutions.

Solution

4x^2-16x+16=0

or,

x^2-4x+4 =0

(x-2)^2=0

Hence, x=2 is the only solution.

It means this quadratic equation had real and equal roots.

Option B is correct.