I need to overload the operator to preform the following ar

I need to overload the operator =, to preform the following arithmetic operation.
num = R2;
R2 = num;

num is a float, while R2 is a fraction with a whole, numer, and denom.

R3 = num, works and this is the code that I have for it.
frapri & frapri :: operator = (const float x) { //R3 = num;
   frapri result;
   result.whole = x;
   result.numer = 0;
   result.denom = 0;
   return result;
}

I tried doing something similar for R2 = num;

float & frapri :: operator = (const frapri &x) {
   float result;
   numer = (x.denom *x.whole + x.numer);
   denom = x.denom;
   result = numer/denom;
   return result;
}

but it doesn\'t work, it gives me an error saying
\"no suitable conversion function from \"frapri\" to \"int\" exists.
I am not sure what I am doing wrong, could someone explain?
This is in c++.

Solution

Here is the modified code for you:

float & frapri :: operator = (const frapri &x) {
float result;   //Declares a float variable result.
numer = (x.denom *x.whole + x.numer);   //Assigns the value to numer.
denom = x.denom;                       //Assigns the value to denom.
result = (float)numer/denom;           //Assigns the fraction value to result.
return result;
}

If this doesn\'t work, just send your whole code atleast the class frapri, so that I can develop it for you.