IF the loss cofficient of a house is 600 BtuhrF and the heat

IF the loss cofficient of a house is 600 Btu/hr/F and the heating degree days are 3000F*day, furnace efficiency is 85%,

how much heating energy is required to heat the house for one year?

Solution

EHT =UA* DD/ n

E = heating energy(Btu)

UA = design heat load Btu/°F day

DD = degree days, °F day

= furnace efficiency

EHT = 600*24*3000/0.85

= 50823529.4118