An ideal transformer is rated at 110004600 V and the seconda

An ideal transformer is rated at 11000/4600 V and the secondary current is rated at 30 A. Calculate: the transformer turns ratio the kVA rating the primary current.

Solution

sol:- transformer rating 11000/4600 volts secondary current = 30 A

1) transformer turns ratio = N₁ / N₂   = V₁ / V₂

= N₁ / N₂ = 11000/4600

= 110 / 46

2) The Kva rating of transformer is = V₂*I₂

= 4600*30 = 138 Kva

3) The primary current is I₁ = V₂I₂ / V₁

= 4600*30/11000

I₁ = 12.54 ampere