A basketball player makes 70 of her free throws When fouled
A basketball player makes 70% of her free throws. When fouled, she gets to take two free throws. Let X represent the number of free throws made in two tries. The probability distribution for the number of free throws she makes in two attempts is summarized in the following table: Number of free throws made 0 1 2 Probability 0.09 0.42 0.49 The probability that she makes at least one free throw is: 0.95. 1.00. 0.67. 0.91.
Solution
P( Atleast one free throw is) = P( X = 1) + P(X=2) = 0.42+0.49 = 0.91
