1State the null and alternative hypotheses 2 Choose the stat

1.State the null and alternative hypotheses.
2. Choose the statistical test.
3. Select the desired level of significance.
4. Calculate the value of the test statistic. • Show all your work for calculations that must be done \"by hand\". • show the relevant output tables.
5. Determine the critical value for the test statistic.

6. Interpret the results.

7. Calculate the effect size, if applicable.
8. calculate the power
9. Write your interpretation in APA format.

The National Center for Education Statistics surveys college and university libraries to obtain information on the number of volumes held. Independent random samples of public and private colleges and universities yield the following data on number of volumes held, in thousands. At the 5% significance level, can we conclude that the median number of volumes held by public colleges and universities is less than that held by private colleges and universities?

Public

79

41

516

15

24

65

411

Private

139

603

113

27

67

500

Solution

Set Up Hypothesis
Null, There Is No-Significance between them Ho: u1 = u2
Alternate, median number of volumes held by public colleges and universities is less than that held by private colleges and universities - H1: u1 < u2
Test Statistic
X(Mean)=164.429
Standard Deviation(s.d1)=207.713 ; Number(n1)=7
Y(Mean)=241.5
Standard Deviation(s.d2)=245.35; Number(n2)=6
we use Test Statistic (t) = (X-Y)/Sqrt(s.d1^2/n1)+(s.d2^2/n2)
to =164.429-241.5/Sqrt((43144.69037/7)+(60196.6225/6))
to =-0.61
| to | =0.61
Critical Value
The Value of |t | with Min (n1-1, n2-1) i.e 5 d.f is 2.015
We got |to| = 0.6056 & | t | = 2.015
Make Decision
Hence Value of |to | < | t | and Here we Do not Reject Ho
P-Value:Left Tail - Ha : ( P < -0.6056 ) = 0.28561
Hence Value of P0.05 < 0.28561,Here We Do not Reject Ho

We don\'t have the evidence to indicate that median number of volumes held by public colleges and universities is less than that held by private colleges and universities