Kelson Sporting Equipment Inc makes two different types of b
Solution
Given information :
Kelson sporting equipment :
Hrs available
Cutting 200
Sewing 300
Packaging 100
We will formulate the table as per the given information.
Let X1 be the variable for Regular model
X 2 be the variable for Calchers model .
Now as per the data mentioned on table we can formulate the equation.
Let Z objective function .Here profit has been mentioned so we have to maximize this equation.
Objective equation
Z Maximize = 5X1 + 8X2
subject to
Constraint equation
X1 + 1.5 X2 </= 200 (Cutting & Sewing Eqn)
0.5 X1 + 0.33 X2 </= 300 (Finishing Eqn)
0.125 X 1 + 0.25 X2 < / = 100 (Packaging & Shipping )
Where X1 & X2 > 0
Now we have to solve this equation ,
We will solve this problem by simplex method
Tableau #1
x1 x2 s1 s2 s3 z
1 1.5 1 0 0 0 200
0.5 0.33 0 1 0 0 300
0.125 0.25 0 0 1 0 100
-5 -8 0 0 0 1 0
Tableau #2
x1 x2 s1 s2 s3 z
0.666667 1 0.666667 0 0 0 133.333
0.28 0 -0.22 1 0 0 256
-0.0416667 0 -0.166667 0 1 0 66.6667
0.333333 0 5.33333 0 0 1 1066.67
Optimal Solution: z = 1066.67; x1 = 0, x2 = 133.333
c) Total Profit earn by kelson
Z = $ 1066.67
d)
Scheduled production in each department
d )
Slack time in each department
Cutting = 200 - 200 = 0
Finishing = 300 - 44 = 265
Packaging = 100 - 33 = 67
| Cutting &Sewing | Finishing | Packaging & Shipping | Profit | |
| Model | ||||
| Regular | 1 | 0.5 | 0.125 | $5 |
| Calcher | 1.5 | 0.33 | 0.25 | $8 |
| Hrs Available | 200 | 300 | 100 |

