use the quadratic formula 4x25x2 what is the solution setSol
use the quadratic formula -4x^2=-5x+2 what is the solution set
Solution
quadratic formula
x = [ -b ± sqrt(b^2 - 4ac) ] / 2a
Here a = 4 , b = -5 , c = 2
putting the value for x
we got
x = -(-5) +- sqrt{(-5)^2 - 4*(4)(2)} / 2*4
= 5 +- sqrt{25-32} / 8
= 5 + sqrt{7} / 8 and 5 - sqrt{7} / 8
x = .955 and .294
Answer
![use the quadratic formula -4x^2=-5x+2 what is the solution setSolutionquadratic formula x = [ -b ± sqrt(b^2 - 4ac) ] / 2a Here a = 4 , b = -5 , c = 2 putting th use the quadratic formula -4x^2=-5x+2 what is the solution setSolutionquadratic formula x = [ -b ± sqrt(b^2 - 4ac) ] / 2a Here a = 4 , b = -5 , c = 2 putting th](/WebImages/32/use-the-quadratic-formula-4x25x2-what-is-the-solution-setsol-1092898-1761575755-0.webp)