solve x76x0 76x is both under radicanSolutiongiven x76x0 Iam

solve

x-7-6x=0

7-6x is both under radican

given

x-7-6x=0

Iam going to write it as sqrt

so x - sqrt(7 -6x) =0

x = sqrt(7-6x)

now squaring on both sides

x^2 = 7-6x

x^2 +6x -7=0

x^2 +7x -x-7=0

x(x+7) -1(x+7)=0

(x-1) (x+7) =0

so x = 1 or x =-7

now to check correct answer or not

x-7-6x=0

1 - sqrt(7-6) =0

1 -1 =0

0 =0 so true

onw plug x=-7

x-7-6x=0

7 - sqrt(7+42) =0

7 -7=0

0=0 so true

therfore x = 1 or x=-7