A travel association claims that the mean daily meal cost fo

A travel association claims that the mean daily meal cost for two adults traveling together on vacation is $100 A random sample of 15 such groups of adults has a mean daily meal cost of $110 and a standard deviation of $7.50 Is there enough evidence to reject the claim at a=0.05 I need the P value? round to three decimal places.

Solution

Formulating the null and alternative hypotheses,              
              
Ho:   u   =   100  
Ha:    u   =/   100  
              
As we can see, this is a    two   tailed test.      
              
df = n - 1 =    14          
  
Getting the test statistic, as              
              
X = sample mean =    110          
uo = hypothesized mean =    100          
n = sample size =    15          
s = standard deviation =    7.5          
              
Thus, t = (X - uo) * sqrt(n) / s =    5.163977795          
              
Also, the p value is              
              
p =    0.000143761 = 0.000 [ANSWER, P VALUE]          
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Comparing P < 0.05, we   REJECT THE NULL HYPOTHESIS.