A medical research team conducted a study to test the effect
Solution
Null Hypothesis, There Is No Significance between them Ho: p1 = p2
 Alternate Hypothesis, There Is Significance between them H1: p1 != p2
 Test Statistic
 Sample 1 : X1 =100, n1 =400, P1= X1/n1=0.25
 Sample 2 : X2 =41, n2 =407, P2= X2/n2=0.101
 Finding a P^ value For Proportion P^=(X1 + X2 ) / (n1+n2)
 P^=0.175
 Q^ Value For Proportion= 1-P^=0.825
 we use Test Statistic (Z) = (P1-P2)/(P^Q^(1/n1+1/n2))
 Zo =(0.25-0.101)/Sqrt((0.175*0.825(1/400+1/407))
 Zo =5.583
 | Zo | =5.583
 Critical Value
 The Value of |Z | at LOS 0.03% is 2.17
 We got |Zo| =5.583 & | Z  | =2.17
 Make Decision
 Hence Value of | Zo | > | Z | and Here we Reject Ho
 P-Value: Two Tailed ( double the one tail ) -Ha : ( P != 5.583 ) = 0
 Hence Value of P0.03 > 0,Here we Reject Ho
We don\'t have evidence to support the proportion of subjects who are pain
 free is the same for the two groups

