Matrix A is factored in the form PDP1 Use the Diagonalizatio
Matrix A is factored in the form PDP^-1. Use the Diagonalization Theorem to find the eigenvalues of A and a basis for each eigenspace. A [2 1 1 2 3 2 1 1 2] = [2 2 2 2 0 -2 2 -1 0] [5 0 0 0 1 0 0 0 1] [1/8 1/8 1/8 1/4 1/4 1/2 1/8 3/8 1/4] Select the correct choice below and fill in the answer boxes to complete your choice. (Use a comma to separate vectors as needed.) There is one distinct eigenvalue, lambda = .A basis for the corresponding eigenspace is In ascending order, the two distinct eigenvalues are lambda_1 = and lambda_2 = Bases for the corresponding eigenspaces are and respectively. In ascending order, the three distinct eigenvalues are lambda_1 = lambda_2 and lambda_3 = Bases for the corresponding eigenspaces are and respectively
Solution
You have got correct anwer, choice B is correct.
![Matrix A is factored in the form PDP^-1. Use the Diagonalization Theorem to find the eigenvalues of A and a basis for each eigenspace. A [2 1 1 2 3 2 1 1 2] = Matrix A is factored in the form PDP^-1. Use the Diagonalization Theorem to find the eigenvalues of A and a basis for each eigenspace. A [2 1 1 2 3 2 1 1 2] =](/WebImages/32/matrix-a-is-factored-in-the-form-pdp1-use-the-diagonalizatio-1093612-1761576237-0.webp)