The 26 letters ABZ are arenaged in random order Equivalentle

The 26 letters A,B,...,Z are arenaged in random order. Equivalentley, the letters are selected sequentialy at random without replacement.

What is the probability that A comes before B in the random order?

Solution

Since the order is truely random, there is a 50% chance that A will come before B in the radom order.