1 If sec 17 8 0 90 then sin cos tan 2 Determine the

1) If sec ( ) = 17/ 8, 0 90, then:

sin = __________?

cos =__________?

tan = __________?

2) Determine the value of sin ^2 x+cos ^2 x for x = 30 degrees.

1) sec ( ) = 17/ 8, 0 90,

cos = 8/17

Height of rt angled triangle = sqrt( 17^2 -8^2) = 15

sin = 15/17

tan = sin /cos = (15/17) / ( 8/17) = 15/8

2) sin ^2 x+cos ^2 x for x = 30 degrees

sin^2(60) + cos^2(60) = (sqrt3/2 )^2 +(1/2)^2 = ( 3+1)/4 =1