Assume the migration rate between two populations Pop1 and P
Solution
Let the migration rate between the two populations be m.; m= 0.3
Let the Allele frequency of population 1(PoP1) = px = 0.0.
Let the Allele frequency of population 2 (PoP2)= py= 1
a) Change in allele frequency after one generation = dP= -m(px -py) = -0.3(0.0-0-1) =-0.3(-1) = 0.3 .
Hence, new allele frequency ,new px = 0.0-0.3= 0.3 = new allele frequency of PoP1
new py = 1-0.3= 0.7 = new allele frequency of PoP2 .
b) Allele frequency reaches equilibrium when change in allele frequency =0.
dP=(px - py )= 0. There fore ; px = py . (allele frequencies of the two populations will get closer till they become rqual in order to reach equilibrium) .
c) According to the equation dP= -m(px -py) ; the change in allle frequency depends on migration rate . Hence, migration rate is propotional to allele frequency. So, the equilibrium frequency will not be the same if the gene flow rate is not the same between the two populations.
